This is pure speculation. With the density of a black hole Composed of energy in packets (photons) with the density described below a black hole would simply be a wave function and as mass enters the event horizon it would become a part of this wave function and not enter a singularity but become a part of a wave function (PSI).

This will take understanding several little points.
1. The object of this idea.
a. Find the the smallest equivalent relativistic mass density of a photon size(micro) black hole. 
2. Equations used.
a. Einstein's Mass Energy equation(E=MC^2).
b. Planck's energy wave length equation(E=hC/L)( L=wave length)( lambda of the greek alphabet is the the standard in this equation, however I don't have that on my key board)
c. Schwarzschild's mass radius equation(R=2GM/C^2) where R= radius of a black hole with a mass of M, and C= the speed of light ( remember to keep all units of measure used appropriate.)
d. Present constants.
1. h=6.626x10^ -34 kg m^2 / sec
2. C=3.0x10^8 m/ sec
3. G= 6.68x10^ -11 m^3 / kgsec^2
3. Assumptions.
a. A photon's observation of a black hole would be the radius of a black hole is observed as half of its wave length.
b. A complete photon is comprised of both one negative half cycle and one positive half cycle, through out which all it's mass is distributed.
c. Half of the photon should be equivalent to its radius such that we can find it's event horizon in the event it's mass satisfies the Schwarzschild equation.
4. Equate M (mass) to E (energy) in Planck's equation gives E=hC/L ; E=MC^2 ; MC^2=hC/L ; next devide both sides by (C^2)(L) gives M/L=(h)/(L^2)(C).*
5. Equate M to Radius in Schwarzschild's equation R=(2G)(M)/(C^2) ; set R= L/2 ; (L)/(2)=[(2)(G)(M)] / [C^2] ; then multiply both sides by (C^2) / [(2)(G)(L)] ; this gives M/L=(C^2) / (4G) **
6.Now conbine the two two equations. where M/L=M/L then (h) / (L^2)(C)* = (C^2) / (4G) ** this gives (h) / (C) = [(C^2) (L^2)] / (4G) this gives( L^2) = [(4G)(h)] / (C^3) this gives L= 2(Gh / c^3)^.5 .



L in meters, will be the wavelength of a photon with a energy density ( both intrinsic or relativistic) equal to a black hole with an event horizon relative to a black hole, however must be treated differently pertaining to source origin (occurence). Let me know if you follow. I have the results. Tell me what you think of it.
Here is the result :L (lambda) (Wave length) = 8.09(16)x10^ -35 meters. Thus making the radius of the micro black hole = 4.05(19)x10^ -35 meters. Thus making the Mass of the micro black hole= 2.72(9) x 10^ -8 kg.
This would place the micro black hole just a little larger than the Planck length. A relativistic black hole that has the velocity of light. As can be seen in this concept, if time reaches a certain limit(below Planck time ) it becomes a problem in crossing between the quantum realm and the relativistic realm, however there may be a link in the way energy is acquired through relativity and how the intrinsic energy can be seperated from the relativistic energy(mass) of a wave function. Just think about it.

What do you mean by "a part" of a wave function? how can you proove that the wave functions would simply merge as one or is there more to the "wave functions" then you think?  more importantly, how can the connenection of planck time and micro black holes help in our understanding of black holes?

Dark Matter Dave : First let me thank you for your reply.

I see what you were asking about " a part" of a wave function, this may help " If a wave function(PSI) is used to represent a large Group Of Particles, the value of (PSI ^2) at some location at a given time is proportional to the probability of finding a large number of particles at that location at that time.)" . The amount of photons necessary to build a black hole would need to reinforce the wave function with the total sum of all the wave functions in synchronization gravitationally, Now to explain, my concept. Each photon has a wave function and is a particle consisting of 3 basic parts the positive field charge, the negative field charge and the magnetic field with it's 2 poles. With out any one of these 3 parts you do not have a photon with relativistic mass propagating through space-time, with out enough time relative to an observer for this process to propagate(determined by the velocity of light) the photon would become an incomplete quanta of energy.  Now we need to explain another part of this idea it will come from the Schwarzschild equation.  The propagation of time at the event horizon stops relative to an inertial observer external to the black hole due to it's energy density (mass to radius), where the radius is represenative of the singilarity as it is the relative point of the propagational current produced by the effect of the interaction of the magnetic field inducing the electric field and vise versa, so this would be in my opinion a measure of the density of the energy that makes up the black hole relative to its gravitational singularity. If you use Mr. Planck's equation to sub equal varibles and determine the point where this massive photon first appears and the photon must have sufficient time to complete its peroid (1 cycle) within a relative space-time coordinate system due to its relativistic mass and relative to that observers coordinate system for an electromagnetic mass, and the density satisfies the Schwarzschild equation for a black hole with it's relativistic energy density equal to the black hole , you would have the problem solved. I hope this helps. Thank you very much for looking. I wish you were here I could explain much better with a chalk board. This stuff could possibly explain dark matter. This idea could also explain wave function integration with gravity within the black hole. A black hole is a space-time contraction structured in an energy transfer (EM wave function) that is frozen in time relative to its space-time inertial position and relativistic mass(energy) density set at maximum relative to an observer, where the maximum is determined using Mr. Planck's and Mr. Einstein's equations, along with the quantum theory that specifies the parameters of a photon.

 Dark Matter Dave :If the photon only reached where if could complete a complete cycle it would form this material with an event horizon and would be just above being planck time but very close. I believe this to be more than a coincidence.

wow...i'm still confused about your concept of the amount of photons needed to "build" a black hole...how can something with zero mass and a nonzero energy make a black hole? what kind of wall do i need to shine my flashlight on to make my own black hole is the question

Dark Matter Dave : Thank you dave. All you need is a photon with enough energy to have the wave length I suggest in the calculation, however there may be some problem in deriving that amount of energy. It meets the mass requirement necessary to construct a black hole with only one photon. What I was trying for was, about the only way these things could be formed would be at the moment of the Planck Epoch, if this was true, then as they travel through space-time how would their gravitational effect and their decay into gamma rays due to redshift, would appear to observers after several billion years.

It would take far to much energy to build with any man made apparatus.

Dark Matter Dave : I found some of my concept on wiki under "Micro black hole"